I have since found an example step in an FCS game play where you do not
show the creation of an intermediate stack but where one must have been
created.
2D 4D KC 3D H-0 C-3 D-0 S-5
--- --- --- ---
-- -- -- -- -- -- -- --
3H QS KH QH 8H 7C
9C 8S 10S AD 5D 7D
9D KS JD JH AH 6S
10C 6D 2H 10H
9H JS 4C KD
8C JC QD QC
7H 10D 7S
6C 9S 6H
5H 8D 5C
4H
====================
Move 4 cards from stack 4 to stack 3
2D 4D KC 3D H-0 C-3 D-0 S-5
--- --- --- ---
-- -- -- -- -- -- -- --
3H QS KH QH 8H 7C
9C 8S 10S AD 5D 7D
9D KS JD JH AH 6S
10C 6D 2H 10H
9H JS 4C KD
8C JC QD QC
7H 10D
6C 9S
5H 8D
7S
6H
5C
4H
Okay, in order to do this step shown above *you had to create an
intermediate temporary stack to hold 2 cards at once time* since
thereonly 2 open stacks and no open Freecell. *But fcs doesn't report
that intermediate stack.*
Shlomi Fish wrote:
> On Tuesday 11 May 2004 01:18, Randall Parker wrote:
> > Does your solver over move cards between columns with an implicit
> > creation of an intermediate multi-card column? Or will that move be
> > broken down into separate move steps?
> >
>
> If I understand you correctly, then this move will be broken down into
> separate moves. If FCS says to move a certain number of cards, then
> all cards
> should be placed on the target column.
>
> Regards,
>
> Shlomi Fish
>
> >
Received on Tue May 11 2004 - 10:18:34 IDT