On 26 Jan 2019 02:06:13 +0000
"theodorepringle1_at_gmail.com [fc-solve-discuss]"
<fc-solve-discuss_at_yahoogroups.com> wrote:
> I constructed a Baker's Game deal that is impossible with nine freecells:
>
> AS QC 8C 5D 4C 9H KC
> AH QD 8D 5C 4D 9S KD
> AD QH 8H 5S 4H 9C KH
> AC QS 8S 5H 4S 9D KS
> 6H TC 3D 7D 2C JC
> 6S TD 3C 7C 2D JD
> 6C TH 3S 7S 2H JH
> 6D TS 3H 7H 2S JS
>
> It is winnable with ten freecells; it may be possible to construct even more
> difficult deals. One thing that seems to increase the difficulty factor is to
> have columns where the front card is of the same suit and one higher in rank
> than another card in the column (the kings all have a queen of the same suit
> in the column, and similarly for the jacks and tens).
thanks for sharing!
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Received on Sat Jan 26 2019 - 04:30:10 IST